3.241 \(\int \frac{\csc ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx\)

Optimal. Leaf size=126 \[ \frac{21 \sin (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}}-\frac{21 E\left (\left .\frac{1}{2} (a+b x)\right |2\right ) \sqrt{d \cos (a+b x)}}{5 b d^4 \sqrt{\cos (a+b x)}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}} \]

[Out]

-(Csc[a + b*x]/(b*d*(d*Cos[a + b*x])^(5/2))) - (21*Sqrt[d*Cos[a + b*x]]*EllipticE[(a + b*x)/2, 2])/(5*b*d^4*Sq
rt[Cos[a + b*x]]) + (7*Sin[a + b*x])/(5*b*d*(d*Cos[a + b*x])^(5/2)) + (21*Sin[a + b*x])/(5*b*d^3*Sqrt[d*Cos[a
+ b*x]])

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Rubi [A]  time = 0.102205, antiderivative size = 126, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2570, 2636, 2640, 2639} \[ \frac{21 \sin (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}}-\frac{21 E\left (\left .\frac{1}{2} (a+b x)\right |2\right ) \sqrt{d \cos (a+b x)}}{5 b d^4 \sqrt{\cos (a+b x)}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}} \]

Antiderivative was successfully verified.

[In]

Int[Csc[a + b*x]^2/(d*Cos[a + b*x])^(7/2),x]

[Out]

-(Csc[a + b*x]/(b*d*(d*Cos[a + b*x])^(5/2))) - (21*Sqrt[d*Cos[a + b*x]]*EllipticE[(a + b*x)/2, 2])/(5*b*d^4*Sq
rt[Cos[a + b*x]]) + (7*Sin[a + b*x])/(5*b*d*(d*Cos[a + b*x])^(5/2)) + (21*Sin[a + b*x])/(5*b*d^3*Sqrt[d*Cos[a
+ b*x]])

Rule 2570

Int[(cos[(e_.) + (f_.)*(x_)]*(b_.))^(n_)*((a_.)*sin[(e_.) + (f_.)*(x_)])^(m_), x_Symbol] :> Simp[((b*Cos[e + f
*x])^(n + 1)*(a*Sin[e + f*x])^(m + 1))/(a*b*f*(m + 1)), x] + Dist[(m + n + 2)/(a^2*(m + 1)), Int[(b*Cos[e + f*
x])^n*(a*Sin[e + f*x])^(m + 2), x], x] /; FreeQ[{a, b, e, f, n}, x] && LtQ[m, -1] && IntegersQ[2*m, 2*n]

Rule 2636

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1))/(b*d*(n +
1)), x] + Dist[(n + 2)/(b^2*(n + 1)), Int[(b*Sin[c + d*x])^(n + 2), x], x] /; FreeQ[{b, c, d}, x] && LtQ[n, -1
] && IntegerQ[2*n]

Rule 2640

Int[Sqrt[(b_)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[b*Sin[c + d*x]]/Sqrt[Sin[c + d*x]], Int[Sqrt[Si
n[c + d*x]], x], x] /; FreeQ[{b, c, d}, x]

Rule 2639

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticE[(1*(c - Pi/2 + d*x))/2, 2])/d, x] /; FreeQ[{
c, d}, x]

Rubi steps

\begin{align*} \int \frac{\csc ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx &=-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}}+\frac{7}{2} \int \frac{1}{(d \cos (a+b x))^{7/2}} \, dx\\ &=-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}+\frac{21 \int \frac{1}{(d \cos (a+b x))^{3/2}} \, dx}{10 d^2}\\ &=-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}+\frac{21 \sin (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}}-\frac{21 \int \sqrt{d \cos (a+b x)} \, dx}{10 d^4}\\ &=-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}+\frac{21 \sin (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}}-\frac{\left (21 \sqrt{d \cos (a+b x)}\right ) \int \sqrt{\cos (a+b x)} \, dx}{10 d^4 \sqrt{\cos (a+b x)}}\\ &=-\frac{\csc (a+b x)}{b d (d \cos (a+b x))^{5/2}}-\frac{21 \sqrt{d \cos (a+b x)} E\left (\left .\frac{1}{2} (a+b x)\right |2\right )}{5 b d^4 \sqrt{\cos (a+b x)}}+\frac{7 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}+\frac{21 \sin (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}}\\ \end{align*}

Mathematica [A]  time = 0.167683, size = 82, normalized size = 0.65 \[ \frac{16 \sin (a+b x)-5 \cos (a+b x) \cot (a+b x)-21 \sqrt{\cos (a+b x)} E\left (\left .\frac{1}{2} (a+b x)\right |2\right )+2 \tan (a+b x) \sec (a+b x)}{5 b d^3 \sqrt{d \cos (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[a + b*x]^2/(d*Cos[a + b*x])^(7/2),x]

[Out]

(-5*Cos[a + b*x]*Cot[a + b*x] - 21*Sqrt[Cos[a + b*x]]*EllipticE[(a + b*x)/2, 2] + 16*Sin[a + b*x] + 2*Sec[a +
b*x]*Tan[a + b*x])/(5*b*d^3*Sqrt[d*Cos[a + b*x]])

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Maple [B]  time = 0.299, size = 408, normalized size = 3.2 \begin{align*} -{\frac{1}{10\,{d}^{5}b}\sqrt{d \left ( 2\, \left ( \cos \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}} \left ( 168\,\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}{\it EllipticE} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \cos \left ( 1/2\,bx+a/2 \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}+336\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{8}-168\,\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}{\it EllipticE} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \cos \left ( 1/2\,bx+a/2 \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-672\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{6}+42\,\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}{\it EllipticE} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \cos \left ( 1/2\,bx+a/2 \right ) +448\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}-112\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}+5 \right ) \left ( -2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}d+ \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}d \right ) ^{{\frac{3}{2}}} \left ( 2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) ^{-1} \left ( \cos \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{-1} \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{-5} \left ( 8\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{6}-12\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}+6\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) ^{-1}{\frac{1}{\sqrt{d \left ( 2\, \left ( \cos \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) }}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(csc(b*x+a)^2/(d*cos(b*x+a))^(7/2),x)

[Out]

-1/10*(d*(2*cos(1/2*b*x+1/2*a)^2-1)*sin(1/2*b*x+1/2*a)^2)^(1/2)/d^5/(2*sin(1/2*b*x+1/2*a)^2-1)/cos(1/2*b*x+1/2
*a)/sin(1/2*b*x+1/2*a)^5/(8*sin(1/2*b*x+1/2*a)^6-12*sin(1/2*b*x+1/2*a)^4+6*sin(1/2*b*x+1/2*a)^2-1)*(168*(2*sin
(1/2*b*x+1/2*a)^2-1)^(1/2)*(sin(1/2*b*x+1/2*a)^2)^(1/2)*EllipticE(cos(1/2*b*x+1/2*a),2^(1/2))*cos(1/2*b*x+1/2*
a)*sin(1/2*b*x+1/2*a)^4+336*sin(1/2*b*x+1/2*a)^8-168*(2*sin(1/2*b*x+1/2*a)^2-1)^(1/2)*(sin(1/2*b*x+1/2*a)^2)^(
1/2)*EllipticE(cos(1/2*b*x+1/2*a),2^(1/2))*cos(1/2*b*x+1/2*a)*sin(1/2*b*x+1/2*a)^2-672*sin(1/2*b*x+1/2*a)^6+42
*(2*sin(1/2*b*x+1/2*a)^2-1)^(1/2)*(sin(1/2*b*x+1/2*a)^2)^(1/2)*EllipticE(cos(1/2*b*x+1/2*a),2^(1/2))*cos(1/2*b
*x+1/2*a)+448*sin(1/2*b*x+1/2*a)^4-112*sin(1/2*b*x+1/2*a)^2+5)*(-2*sin(1/2*b*x+1/2*a)^4*d+sin(1/2*b*x+1/2*a)^2
*d)^(3/2)/(d*(2*cos(1/2*b*x+1/2*a)^2-1))^(1/2)/b

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\csc \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(b*x+a)^2/(d*cos(b*x+a))^(7/2),x, algorithm="maxima")

[Out]

integrate(csc(b*x + a)^2/(d*cos(b*x + a))^(7/2), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{d \cos \left (b x + a\right )} \csc \left (b x + a\right )^{2}}{d^{4} \cos \left (b x + a\right )^{4}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(b*x+a)^2/(d*cos(b*x+a))^(7/2),x, algorithm="fricas")

[Out]

integral(sqrt(d*cos(b*x + a))*csc(b*x + a)^2/(d^4*cos(b*x + a)^4), x)

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Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(b*x+a)**2/(d*cos(b*x+a))**(7/2),x)

[Out]

Timed out

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\csc \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac{7}{2}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(csc(b*x+a)^2/(d*cos(b*x+a))^(7/2),x, algorithm="giac")

[Out]

integrate(csc(b*x + a)^2/(d*cos(b*x + a))^(7/2), x)